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(x + 1)(x 2)(x + 3)(x 4) = 0 We take each binomial individually, set it equal to 0, and then solve the resulting first-degree equations: x+1=0 x 2=0 x+3=0 x 4=0 Any value of x that satisfies one of these is a root of the higher-degree equation. There are four such values: x = 1 or x = 2 or x = 3 or x = 4 so the real solution set of the higher-degree equation is X = { 1, 2, 3, 4}. Now consider another higher-degree equation. This one is a little tricky, because three of the four binomials have exponents attached: (x + 1)(x 2)2(x + 3)3(x 4)4 = 0 If we remove the exponents from the binomials and set each equal to 0, we get the same four first-degree equations as before. That means the real roots of the higher-degree equation are the same, too. But three of the four roots have multiplicity greater than 1. The root x = 2 has multiplicity 2, the root x = 3 has multiplicity 3, and the root x = 4 has multiplicity 4.

At the conclusion of our study of shortest paths ( 4), we observed that the problem is especially easy in directed acyclic graphs (dags). Let s recapitulate this case, because it lies at the heart of dynamic programming. The special distinguishing feature of a dag is that its nodes can be linearized; that is, they can be arranged on a line so that all edges go from left to right (Figure 6.1). To see why this helps with shortest paths, suppose we want to gure out distances from node S to the other nodes. For concreteness, let s focus on node D. The only way to get to it is through its predecessors, B or C; so to nd the shortest path to D, we need only compare these two routes: dist(D) = min{dist(B) + 1, dist(C) + 3}. A similar relation can be written for every node. If we compute these dist values in the Figure 6.1 A dag and its linearization (topological ordering).

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When we plug x = 2/3 into the final polynomial equation we found in solution to Prob. 3 and then grind through the arithmetic, the process goes like this, step-by-step: 105x 3 + 211x 2 + 112x + 12 = 0 105 ( 2/3)3 + 211 ( 2/3)2 + 112 ( 2/3) + 12 = 0 105 ( 8/27) + 211 (4/9) + 112 ( 2/3) + 12 = 0 840/27 + 844/9 224/3 + 12 = 0 840/27 + 2,532/27 2,016/27 + 324/27 = 0 ( 840 + 2,532 2,016 + 324) / 27 = 0 840 + 2,532 2,016 + 324 = 0 0=0 To check the root x = 6/5, we go through this sequence of calculations: 105x 3 + 211x 2 + 112x + 12 = 0 105 ( 6/5)3 + 211 ( 6/5)2 + 112 ( 6/5) + 12 = 0 105 ( 216/125) + 211 (36/25) + 112 ( 6/5) + 12 = 0 22,680/125 + 7,596/25 672/5 + 12 = 0 22,680/125 + 37,980/125 16,800/125 + 1,500/125 = 0 ( 22,680 + 37,980 16,800 + 1,500) / 125 = 0 22,680 + 37,980 16,800 + 1,500 = 0 0=0 To check the root x = 1/7, we go through this arithmetic, step-by-step: 105x 3 + 211x 2 + 112x + 12 = 0 105 ( 1/7)3 + 211 ( 1/7)2 + 112 ( 1/7) + 12 = 0 105 ( 1/343) + 211 (1/49) + 112 ( 1/7) + 12 = 0 105/343 + 211/49 112/7 + 12 = 0 105/343 + 1,477/343 5,488/343 + 4,116/343 = 0 ( 105 + 1,477 5,488 + 4,116) / 343 = 0 105 + 1,477 5,488 + 4,116 = 0 0=0

The main body of this chapter has presented a GPS aided encoder-based dead-reckoning approach built on the assumption of a planar operating surface. The approach is easily generalized to nonplanar surfaces when roll angle and the pitch angle can be measured. The main changes to the approach would occur in the kinematic model derived in Section 9.3. The kinematic model of eqn. (9.3) would be replaced by cos( ) cos( ) p = sin( ) cos( ) u (9.44) sin( ) = cos( ) . cos( ) (9.45)

9:

infrequent Common to all the drugs in the class is variable weight gain With long-term treatment this may accumulate to 20 percent of the patient s original weight Hypercholesterolemia and diabetes then often emerge and may require additional treatment In a few cases the newer generation antipsychotics have induced some obsessive-compulsive symptoms Finally, it might be commented that according to Leucht and colleagues who performed a meta-analysis of extrapyramidal symptoms and various drugs, that low potency rst-generation antipsychotics (excluding haloperidol) may have comparable complications to the new generation of drugs when dose-equivalent amounts are given Not all clinicians agree with this perspective.

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